(w-2)=2w^2+2w+12

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Solution for (w-2)=2w^2+2w+12 equation: 



(w-2)=2w^2+2w+12

We move all terms to the left:

(w-2)-(2w^2+2w+12)=0

We get rid of parentheses

-2w^2+w-2w-2-12=0

We add all the numbers together, and all the variables

-2w^2-1w-14=0

a = -2; b = -1; c = -14;
Δ = b2-4ac
Δ = -12-4·(-2)·(-14)
Δ = -111
Delta is less than zero, so there is no solution for the equation

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